SQL连续出现三次的数字—发生BIGINT UNSIGNED value is out of range解决方法

小灰灰 2023-10-02 22:59 90阅读 0赞

题目背景

编写一个 SQL 查询,查找所有至少连续出现三次的数字。

  1. +----+-----+
  2. | Id | Num |
  3. +----+-----+
  4. | 1 | 1 |
  5. | 2 | 1 |
  6. | 3 | 1 |
  7. | 4 | 2 |
  8. | 5 | 1 |
  9. | 6 | 2 |
  10. | 7 | 2 |
  11. +----+-----+

例如,给定上面的 Logs 表, 1 是唯一连续出现至少三次的数字。

  1. +-----------------+
  2. | ConsecutiveNums |
  3. +-----------------+
  4. | 1 |
  5. +-----------------+

解决方法:开窗函数

  1. select distinct num as ConsecutiveNums from
  2. (
  3. select num,id-rnk as chazhi from
  4. (
  5. select id, num, row_number()over(partition by num order by id) as rnk from logs
  6. ) t
  7. ) p
  8. group by num,chazhi
  9. having count(*) >= 3

会发生如下错误:BIGINT UNSIGNED value is out of range in ‘(t.id - t.rnk)’

错误解释

参考链接
链接: https://dev.mysql.com/doc/refman/5.6/en/out-of-range-and-overflow.html

关于超出范围和溢出处理:

1.当计算有符号数值可能发生的错误

数值表达式计算期间的溢出会导致错误。例如,最大的有符号BIGINT值为 9223372036854775807,因此以下表达式生成 错误:

  1. mysql> SELECT 9223372036854775807 + 1;
  2. ERROR 1690 (22003): BIGINT value is out of range in '(9223372036854775807 + 1)'

要使操作在这种情况下成功,请将值为无符号;

  1. mysql> SELECT CAST(9223372036854775807 AS UNSIGNED) + 1;
  2. +-------------------------------------------+
  3. | CAST(9223372036854775807 AS UNSIGNED) + 1 |
  4. +-------------------------------------------+
  5. | 9223372036854775808 |
  6. +-------------------------------------------+

是否发生溢出取决于操作数的范围,因此 处理上述表达式的另一种方法是使用 精确值算法,因为DECIMAL值具有更大的 比整数的范围:

  1. mysql> SELECT 9223372036854775807.0 + 1;
  2. +---------------------------+
  3. | 9223372036854775807.0 + 1 |
  4. +---------------------------+
  5. | 9223372036854775808.0 |
  6. +---------------------------+
2.当计算数值无符号可能发生的错误

整数值之间的减法(其中一个有类型)产生无符号结果 违约。如果结果本来是负面的,则 错误结果:UNSIGNED
此时情况与题目出现错误一致

  1. mysql> SELECT CAST(0 AS UNSIGNED) - 1;
  2. ERROR 1690 (22003): BIGINT UNSIGNED value is out of range in '(cast(0 as unsigned) - 1)'
要使操作在这种情况下成功,请使用有符号进行相减
  1. select distinct num as ConsecutiveNums from
  2. (
  3. select num,id-cast(rnk as signed) as chazhi from
  4. (
  5. select id, num, row_number()over(PARTITION by num order by id) as rnk from logs
  6. ) t
  7. ) p
  8. group by num,chazhi
  9. having count(*) >= 3

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