648. 单词替换

心已赠人 2023-10-04 08:14 1阅读 0赞

在英语中，我们有一个叫做 `词根`(root)的概念，它可以跟着其他一些词组成另一个较长的单词——我们称这个词为 `继承词`(successor)。例如，词根`an`，跟随着单词 `other`(其他)，可以形成新的单词 `another`(另一个)。

现在，给定一个由许多词根组成的词典和一个句子。你需要将句子中的所有`继承词`用`词根`替换掉。如果`继承词`有许多可以形成它的`词根`，则用最短的词根替换它。

你需要输出替换之后的句子。

**示例 1：**

输入：dictionary = ["cat","bat","rat"], sentence = "the cattle was rattled by the battery"
    输出："the cat was rat by the bat"

**示例 2：**

输入：dictionary = ["a","b","c"], sentence = "aadsfasf absbs bbab cadsfafs"
    输出："a a b c"

**示例 3：**

输入：dictionary = ["a", "aa", "aaa", "aaaa"], sentence = "a aa a aaaa aaa aaa aaa aaaaaa bbb baba ababa"
    输出："a a a a a a a a bbb baba a"

**示例 4：**

输入：dictionary = ["catt","cat","bat","rat"], sentence = "the cattle was rattled by the battery"
    输出："the cat was rat by the bat"

**示例 5：**

输入：dictionary = ["ac","ab"], sentence = "it is abnormal that this solution is accepted"
    输出："it is ab that this solution is ac"

**提示：**

*  `1 <= dictionary.length <= 1000`
 *  `1 <= dictionary[i].length <= 100`
 *  `dictionary[i]` 仅由小写字母组成。
 *  `1 <= sentence.length <= 10^6`
 *  `sentence` 仅由小写字母和空格组成。
 *  `sentence` 中单词的总量在范围 `[1, 1000]` 内。
 *  `sentence` 中每个单词的长度在范围 `[1, 1000]` 内。
 *  `sentence` 中单词之间由一个空格隔开。
 *  `sentence` 没有前导或尾随空格。

package Solution648;
    
    import java.util.ArrayList;
    import java.util.Arrays;
    import java.util.List;
    
    class Solution {
    	public String replaceWords(List<String> dictionary, String sentence) {
    		String arr[] = sentence.split("\\s+");
    		for (int j = 0; j < arr.length; j++) {
    			for (int i = 0; i < dictionary.size(); i++) {
    				// System.out.println(dictionary.get(i) + "(.*)");
    				arr[j] = arr[j].replaceAll("^" + dictionary.get(i) + "(.*)", dictionary.get(i));
    			}
    		}
    		// System.out.println(Arrays.toString(arr));
    		String out = "";
    		for (int j = 0; j < arr.length; j++) {
    			out = out + arr[j] + " ";
    		}
    		return out.trim();
    
    	}
    
    	public static void main(String[] args) {
    
    		Solution sol = new Solution();
    
    		List<String> dictionary = new ArrayList<String>();
    		dictionary.add("a");
    		dictionary.add("aa");
    		dictionary.add("aaa");
    		dictionary.add("aaaa");
    
    		String sentence = "a aa a aaaa aaa aaa aaa aaaaaa bbb baba ababa";
    
    		System.out.println(sol.replaceWords(dictionary, sentence));
    
    	}
    
    }