SQL查询

朱雀 2023-10-05 16:50 16阅读 0赞

sql简单函数,记录

mysql 查询当天、本周,本月,上一个月的数据

文章目录

        • 今天
        • 昨天
        • 近7天
        • 近30天
        • 本月
        • 上一月
        • 查询本季度数据
        • 查询上季度数据
        • 查询本年数据
        • 查询上年数据
        • 查询当前这周的数据
        • 查询上周的数据
        • 查询上个月的数据
        • 查询当前月份的数据
        • 查询距离当前现在6个月的数据
今天

select * from 表名 where to_days(时间字段名) = to_days(now());

栗子:查询当天参加活动人数(DATA data)

SELECT count(*) FROM active_partake_stat WHERE TO_DAYS(modifiedTime) = TO_DAYS(#{data}) AND activeId=activeId and appId=#{appId}

昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

近7天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

近30天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )

上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 时间字段名, ‘%Y%m’ ) ) =1

查询本季度数据

select * from ht_invoice_information where QUARTER(create_date)=QUARTER(now());

查询上季度数据

select * from ht_invoice_information where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

查询本年数据

select * from ht_invoice_information where YEAR(create_date)=YEAR(NOW());

查询上年数据

select * from ht_invoice_information where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now());

查询上周的数据

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now())-1;

查询上个月的数据
  1. select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
  2. select * from user where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ;
  3. select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
  4. select * from user where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now())
  5. select * from user where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now())
  6. select * from user where pudate between 上月最后一天 and 下月第一天
查询当前月份的数据

select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(now(),’%Y-%m’)

查询距离当前现在6个月的数据

select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

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