django2.2 配置urls(亲测)
项目名下:
urls.py
from django.contrib import admin
from django.urls import path,include
urlpatterns = [
path(‘admin/‘, admin.site.urls),
path(‘’,include(‘booktest.urls’)),
]
APP下:
urls.py
from django.contrib import admin
from django.urls import path
from . import views
urlpatterns = [
# path(‘admin/‘, admin.site.urls),
path(‘index/‘, views.index)
]
然后开启服务:访问以下地址
http://127.0.0.1:8000/index/
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原文链接:https://blog.csdn.net/lq497028254/article/details/90450146
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