JBPM4.4 使用非zip方式发布流程实现流程图加载

心已赠人 2024-02-17 15:17 23阅读 0赞

JBPM4.4 显示流程图片，需要携带流程图发布；这样大多数是采用打包zip方式来部署流程，太过繁琐；所以我采用如下方式发布流程

RepositoryService repositoryService=  processEngine.getRepositoryService();
            NewDeployment deploy= repositoryService.createDeployment();
            deploy.addResourceFromClasspath("newSite.jpdl.xml")
            .addResourceFromClasspath("newSite.png");

action接收processInstanceId，（一般情况下processInstanceId与ExecutionId相同）得到流程图，并在当前activity上画框，来显示流程走到哪里。

public String showImage(){
    		ProcessInstance processInstance = executionService  
    				.findProcessInstanceById(pid);  
    				  
    				String processDefinitionId = processInstance.getProcessDefinitionId();  
    				ProcessDefinition processDefinition = repositoryService  
    				.createProcessDefinitionQuery().processDefinitionId(  
    				processDefinitionId).uniqueResult();  
    				  
    				Set<String> activityNames = processInstance.findActiveActivityNames();  
    				BufferedImage image = null;  
    				  
    				for (String activityName : activityNames) {  
    				    ActivityCoordinates ac = repositoryService.getActivityCoordinates(  
    				    processInstance.getProcessDefinitionId(), activityName);  
    				  
    				    InputStream is = repositoryService.getResourceAsStream(  
    				    processDefinition.getDeploymentId(), processDefinition  
    				    .getImageResourceName());  
    				  
    				    image = ImageIO.read(is);  
    				    Graphics g = image.getGraphics();  
    				    g.setColor(new Color(255, 0, 0));  
    				  
    				    g.drawRect(ac.getX(), ac.getY(), ac.getWidth(), ac.getHeight());  
    				    g.dispose();  
    				}  
    				  
    				ByteArrayOutputStream output = new ByteArrayOutputStream();  
    				ImageIO.write(image, "PNG", output);  
    				ByteArrayInputStream input = new ByteArrayInputStream(output  
    				.toByteArray());  
    				this.setInputStream(input);  
    				return SUCCESS;
    	}

structs里面配置result为stream类型，class交给spring处理没有集成的可以修改成原有路径

<action name="processImage" class="processImageAction">  
        <result type="stream">  
            <param name="contentType">image/png</param>  
            <param name="inputName">inputStream</param>  
        </result>  
    </action>

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