PAT 甲级 1027 Colors in Mars (20 分) 进制转换问题我的代码+别人的代码

╰+哭是因爲堅強的太久メ 2024-02-19 20:59 60阅读 0赞

1027 Colors in Mars (20 分)

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for `Red`, the middle 2 digits for `Green`, and the last 2 digits for `Blue`. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

#### Input Specification: ####

Each input file contains one test case which occupies a line containing the three decimal color values.

#### Output Specification: ####

For each test case you should output the Mars RGB value in the following format: first output `#`, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a `0` to its left.

#### Sample Input: ####

15 43 71

#### Sample Output: ####

#123456

我的代码：

#include<iostream>
    #include<cstring>
    #include<cstdio>
    using namespace std;
    string convert(int n)
    {
    	string s="";
    	while(n!=0)
    	{
    		if(n%13>9)
    		s+=(n%13-10+65);
    		else
    		s+=(n%13+'0');
    		n/=13;
    	}
    	return s;
    }
    void print(string t)
    {
    	if(t.length()==0)
    	printf("00");
    	else
    	if(t.length()==1)
    	printf("0%c",t[0]);
    	else
    	printf("%c%c",t[1],t[0]);
    }
    int main()
    {
    	int a,b,c,i,j,k;
    	string t;
    	cin>>a>>b>>c;
    	printf("#");
    	t=convert(a);
    	print(t);
    	t=convert(b);
    	print(t);
    	t=convert(c);
    	print(t);
    	printf("\n");
    	return 0;
    }

别人的代码：

差距还是有的！

#include<cstdio>
    #include<cstring>
    #include<iostream>
    using namespace std;
    char radix[13] ={
      '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C'
    };
    int main() {
        int r, g, b;
        scanf("%d%d%d", &r, &g, &b);
        printf("#");
        printf("%c%c", radix[r / 13], radix[r % 13]);
        printf("%c%c", radix[g / 13], radix[g % 13]);
        printf("%c%c", radix[b / 13], radix[b % 13]);
        return 0;
    }

加油！少年