java String版本号对比

迈不过友情╰ 2024-03-03 08:22 116阅读 0赞

public static boolean compareVersion(String version1, String version2) {
        
            // 切割点 "."；
            String[] versionArray1 = version1.split("\\.");
            String[] versionArray2 = version2.split("\\.");
            int idx = 0;
            // 取最小长度值
            int minLength = Math.min(versionArray1.length, versionArray2.length);
            int diff = 0;
            // 先比较长度 再比较字符
            while (idx < minLength && (diff = versionArray1[idx].length() - versionArray2[idx].length()) == 0
                    && (diff = versionArray1[idx].compareTo(versionArray2[idx])) == 0) {
        
                ++idx;
            }
            // 如果已经分出大小，则直接返回，如果未分出大小，则再比较位数，有子版本的为大；
            diff = (diff != 0) ? diff : versionArray1.length - versionArray2.length;
            return diff>0;
        }

测试：

public static void main(String[] args) {
        
            String version1 = "4.3.6.1";
            String version2 = "4.5.0";
            String[] versionArray1 = version1.split("\\.");
            String[] versionArray2 = version2.split("\\.");
            int idx = 0;
            // 取最小长度值
            int minLength = Math.min(versionArray1.length, versionArray2.length);
            int diff = 0;
            // 先比较长度 再比较字符
            while (idx < minLength && (diff = versionArray1[idx].length() - versionArray2[idx].length()) == 0
                    && (diff = versionArray1[idx].compareTo(versionArray2[idx])) == 0) {
        
                ++idx;
            }
            // 如果已经分出大小，则直接返回，如果未分出大小，则再比较位数，有子版本的为大；
            diff = (diff != 0) ? diff : versionArray1.length - versionArray2.length;
            System.out.println(diff>0);
        }