set集合
目录
1,set集合的特点:
1.1,set集合添加的数据不可重复
1.2 hashset无序 Treeset有序
1.2.1set集合的遍历方法
1.2.2Treeset自定义对象无法排序,hashSet因为是无序所以会无规则遍历
1.2.3如何让Treeset集合进行排序(自然排序.比较器排序 )
1,set集合的特点:
1.1,set集合添加的数据不可重复
public static void main(String[] args) {
Set s = new HashSet();
s.add("b");
s.add("a");
s.add("c");
s.add("b");
System.out.println(s);
}
通过上一行代码输出的结果为:
由此可以说明set集合里的数据不可重复。
但是若存放的数据为对象时:
public static void main(String [] args) {
HashSet<Object> set =new HashSet<Object>();
set.add(new person("zs",12));
set.add(new person("ww",12));
set.add(new person("ls",12));
System.out.println(set.size());
set.add(new person("ww",12));
System.out.println(set.size());
}
运行此段代码的结果如图:
由此可以说明但我们在set集合添加属性值一样的对象时,因为地址同所以可以存放进去,那我们该怎么解决?我们尝试用list集合去重原理试一下。
package com.xzs.set;
import java.util.HashSet;
import java.util.Set;
public class demo1 {
public static void main(String [] args) {
HashSet<Object> set =new HashSet<Object>();
set.add(new person("zs",12));
set.add(new person("ww",12));
set.add(new person("ls",12));
System.out.println(set.size());
set.add(new person("ww",12));
System.out.println(set.size());
}
}
class person{
private String name;
private int age;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public person(String name, int age) {
super();
this.name = name;
this.age = age;
}
public person() {
super();
}
@Override
public String toString() {
return "person [name=" + name + ", age=" + age + "]";
}
@Override
// public int hashCode() {
// final int prime = 31;
// int result = 1;
// result = prime * result + age;
// result = prime * result + ((name == null) ? 0 : name.hashCode());
// return result;
// }
// @Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
person other = (person) obj;
if (age != other.age)
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
return true;
}
}
以上代码运行结果是
同样集合的长度还是3和4由此说明set集合与list集合判定的底层逻辑就不同
package com.xzs.set;
import java.util.HashSet;
import java.util.Set;
public class demo1 {
public static void main(String [] args) {
HashSet<Object> set =new HashSet<Object>();
set.add(new person("zs",12));
set.add(new person("ww",12));
set.add(new person("ls",12));
System.out.println(set.size());
set.add(new person("ww",12));
System.out.println(set.size());
}
}
class person{
private String name;
private int age;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public person(String name, int age) {
super();
this.name = name;
this.age = age;
}
public person() {
super();
}
@Override
public String toString() {
return "person [name=" + name + ", age=" + age + "]";
}
@Override
public int hashCode() {
System.out.println("hashcode被调用了");
final int prime = 31;
int result = 1;
result = prime * result + age;
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
System.out.println("equals被调用了");
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
person other = (person) obj;
if (age != other.age)
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
return true;
}
}
同样是上一行代码,这时候运行的结果为
由此可以说明,set集合在判定数据是先通过hascode,并且在上类代码中当我们的hashcode被注释的时候equlas,也不会被调用,所以set集合的判定是否为重复数组的原理是:“先来通过hashcode判定,才会进入equals判定”
1.2 hashset无序 Treeset有序
要想判定set集合是否为有序的我们可以遍历他的元素即可
1.2.1set集合的遍历方法
1.为迭代器也就是图中的Iterator
2.增强for也就是foreach
public static void main(String[] args) {
Set s = new HashSet();
s.add("a");
s.add("c");
s.add("b");
for (Object o : s) {
System.out.println(o);
}
System.out.println("==============================");
Iterator it = s.iterator();
while (it.hasNext()) {
System.out.println(it.next());
}
}
结果为:
证明 string 类型是可以自动排序的
1.2.2Treeset自定义对象无法排序,hashSet因为是无序所以会无规则遍历
package com.xzs.set;
import java.util.HashSet;
import java.util.Iterator;
import java.util.Set;
import java.util.TreeSet;
public class demo1 {
public static void main(String [] args) {
TreeSet<Object> set =new TreeSet<Object>();
set.add(new person("zs",3,12));
set.add(new person("ww",6,92));
set.add(new person("ls",1,17));
System.out.println(set.size());
for (Object object : set) {
System.out.println(object);
}
}
}
class person{
private String name;
private int level;
private int age;
public int getLevel() {
return level;
}
public void setLevel(int level) {
this.level = level;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public person(String name, int age) {
super();
this.name = name;
this.age = age;
}
@Override
public String toString() {
return "person [name=" + name + ", level=" + level + ", age=" + age + "]";
}
public person(String name, int level, int age) {
super();
this.name = name;
this.level = level;
this.age = age;
}
public person() {
super();
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + age;
result = prime * result + level;
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
person other = (person) obj;
if (age != other.age)
return false;
if (level != other.level)
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
return true;
}
}
结果为:会出现数据转化异常
1.2.3如何让Treeset集合进行排序(自然排序.比较器排序 )
package com.xzs.set;
import java.util.HashSet;
import java.util.Iterator;
import java.util.Objects;
import java.util.Set;
import java.util.TreeSet;
public class demo1 {
public static void main(String[] args) {
Set s = new TreeSet();
s.add(new Student("zs",17));
s.add(new Student("ls",19));
s.add(new Student("ww",18));
System.out.println("目前集合容器中的元素:"+s);
}
}
class Student implements Comparable{
private String name;
private int age;
public Student(String name, int age) {
this.name = name;
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public boolean equals(Object o) {
System.out.println("调用了equals方法。。。");
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Student student = (Student) o;
return age == student.age && name.equals(student.name);
}
@Override
public int hashCode() {
System.out.println("调用了hashCode方法。。。");
return Objects.hash(name, age);
}
@Override
public String toString() {
return "Student{" +
"name='" + name + '\'' +
", age=" + age +
'}';
}
@Override
public int compareTo(Object o) {
Student student = (Student) o;
return this.age - student.age;
}
}
结果为:
当然我们也可以用TreeSet构造器使用实现java.util.Comparator的匿名内部类
如
package com.xzs.set;
import java.util.Comparator;
import java.util.HashSet;
import java.util.Iterator;
import java.util.Objects;
import java.util.Set;
import java.util.TreeSet;
public class demo1 {
public static void main(String[] args) {
TreeSet s=new TreeSet(new Comparator() {
public int compare(Object o1, Object o2) {
System.out.println("调用了compare方法。。。");
Student s1 = (Student) o1;
Student s2 = (Student) o2;
if (s1.getAge()-s2.getAge() == 0)
return s1.getName().compareTo(s2.getName());
return s1.getAge()-s2.getAge();
}
});
s.add(new Student("zs",16));
s.add(new Student("ls",17));
s.add(new Student("zs",17));
s.add(new Student("ww",18));
System.out.println("目前集合容器中的元素:"+s);
}
}
class Student {
private String name;
private int age;
public Student(String name, int age) {
this.name = name;
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public boolean equals(Object o) {
System.out.println("调用了equals方法。。。");
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Student student = (Student) o;
return age == student.age && name.equals(student.name);
}
@Override
public int hashCode() {
System.out.println("调用了hashCode方法。。。");
return Objects.hash(name, age);
}
@Override
public String toString() {
return "Student{" +
"name='" + name + '\'' +
", age=" + age +
'}';
}
}
得到的结果为:
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