利用Python解读物理电学基础应用

秒速五厘米 2024-03-22 20:23 9阅读 0赞

1.  **问题**

如何利用python解读物理电学部分有几个重要的公式，串联电路求阻公式R=R1+R2以及并联电路求电流公式I=I1+I2？

**2** **方法**

利用了三个函数代码片段：

1.def N\_times(Ts)

2.def R\_total\_chuanl(one,two)

3.def I\_total\_bingl(one,two)

利用了if…elif条件判断语句

代码清单 1

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 <td>def N_times(Ts): &nbsp; &nbsp;Npd = input('并联支路电流:zl ｜ 并联总电流:gl | 总电压：cu') &nbsp; &nbsp;if Npd.lower() == 'zl': &nbsp; &nbsp; &nbsp; &nbsp;I_one = "干路电流为___" &nbsp; &nbsp; &nbsp; &nbsp;I_two = '支路电流为___' &nbsp; &nbsp; &nbsp; &nbsp;N1 = float(input('输入{}{}：'.format(I_one,Ts))) &nbsp; &nbsp; &nbsp; &nbsp;N2 = float(input('输入{}{}：'.format(I_two,Ts))) &nbsp; &nbsp;elif Npd.lower() == 'gl': &nbsp; &nbsp; &nbsp; &nbsp;I_one_1 = '支路1电流为___' &nbsp; &nbsp; &nbsp; &nbsp;I_one_2 = '支路2电流为___' &nbsp; &nbsp; &nbsp; &nbsp;N1 = float(input('输入{}{}：'.format(I_one_1,Ts))) &nbsp; &nbsp; &nbsp; &nbsp;N2 = float(input('输入{}{}：'.format(I_one_2,Ts))) &nbsp; &nbsp;elif Npd.lower() == 'cu': &nbsp; &nbsp; &nbsp; &nbsp;R_one_1 = 'R1两端电压为___' &nbsp; &nbsp; &nbsp; &nbsp;R_one_2 = 'R2两端电压为___' &nbsp; &nbsp; &nbsp; &nbsp;N1 = float(input('输入{}{}：'.format(R_one_1,Ts))) &nbsp; &nbsp; &nbsp; &nbsp;N2 = float(input('输入{}{}：'.format(R_one_2,Ts))) &nbsp; &nbsp;return N1, N2,Npd def R_total_chuanl(one,two): &nbsp; &nbsp;R = one + two &nbsp; &nbsp;print('欢迎来到求串联电阻的步骤：R总= R1+R2 = {}Ω +{}Ω ={}Ω '.format(A, B, R)) def I_total_bingl(one,two,Npd): &nbsp; &nbsp;if Npd == 'gl': &nbsp; &nbsp; &nbsp; &nbsp;I = one + two &nbsp; &nbsp; &nbsp; &nbsp;print('求得干路并联电流为：I总= I1+I2 = {}A +{}A ={}A '.format(one, two, I)) &nbsp; &nbsp;elif Npd == 'zl': &nbsp; &nbsp; &nbsp; &nbsp;if two &lt; one: &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;one,two = two,one &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;I2 = two - one &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;print('支路L2电流为:I2=I-I1={}A-{}A={:.1f}A'.format(two,one,I2)) def U_total_chl(one,two,Npd): &nbsp; &nbsp;if Npd == 'cu': &nbsp; &nbsp; &nbsp; &nbsp;U = one + two &nbsp; &nbsp; &nbsp; &nbsp;print('串联电路总电压为：U总= U1+U2 = {}V +{}V ={}V '.format(one, two, U)) &nbsp; &nbsp; &nbsp; &nbsp;print(f'串联电路电压规律为u=u1+u2，U总={U}V') Pd = input(''' &nbsp; &nbsp;请输入 &nbsp; &nbsp;1-并联电流 &nbsp; &nbsp;2-串联电阻 &nbsp; &nbsp;3-串联电压\n''') if Pd == '1': &nbsp; &nbsp;Ts = 'A' &nbsp; &nbsp;A,B,Npd = N_times(Ts) &nbsp; &nbsp;I_total_bingl(A,B,Npd) elif Pd == '2': &nbsp; &nbsp;Ts = 'Ω ' &nbsp; &nbsp;A,B = N_times(Ts) &nbsp; &nbsp;R_total_chuanl(A,B) elif Pd == '3': &nbsp; &nbsp;Ts = 'V' &nbsp; &nbsp;A,B,Npd = N_times(Ts) &nbsp; &nbsp;U_total_chl(A,B,Npd) <img src="https://img-blog.csdnimg.cn/img_convert/d9b5e6312816b860a10c7790bb85d353.jpeg" alt="d9b5e6312816b860a10c7790bb85d353.jpeg"></td> 
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**3** **结语**

针对如何利用python解读物理电学基础应用的问题，运用了三个函数代码片段，以及利用了if…elif条件判断语句的方法等，通过实验，证明该方法是有效的。本文方法比较简陋且并不是唯一方法，未来可以尝试用其他的方法去验证更多的相关基础应用。