异常处理不当：Java中未捕获的异常导致程序中断的问题案例。

原创左手的ㄟ右手 2024-11-15 17:48 10阅读 0赞

案例1：简单的打印错误

```java
public class PrintError {
    public static void main(String[] args) {
        try {
            System.out.println("Hello, World! " + 5 / 0);
        } catch (ArithmeticException e) {
            System.out.println("Division by zero caught: " + e.getMessage());
        }
    }
}
```

在这个例子中，我们试图执行一个除以零的操作。Java会抛出`ArithmeticException`。如果不捕获这个异常，程序就会中断。

案例2：复杂业务逻辑

```java
import java.util.Random;

public class BankAccount {
    private double balance;
    private Random rand = new Random();

public void deposit(double amount) {
        if (amount < 0) {
            System.out.println("Deposit cannot be negative.");
            return;
        }
        balance += amount;
        System.out.println("Deposited: " + amount);
    }

public void withdraw(double amount) {
        if (amount < 0 || amount > balance) {
            System.out.println("Withdrawal exceeds available balance or is negative.");
            return;
        }
        balance -= amount;
        System.out.println("Withdrawn: " + amount);
    }

public double getBalance() {
        return balance;
    }

public static void main(String[] args) {
        BankAccount account = new BankAccount();
        account.deposit(1000);
        account.withdraw(500);

System.out.println("Current Balance: " + account.getBalance());
    }
}
```

在这个案例中，我们创建了一个银行账户类。在`main`方法中，我们存款、取款，并打印当前余额。如果取款金额大于存款金额或者操作为负数，程序会抛出异常，如果不捕获，程序就会中断。