Two sum-LeetCode(C语言实现)-蒲公英云

Two sum-LeetCode(C语言实现)

梦里梦外; 2022-02-27 05:18 218阅读 0赞

今天用C写了LeetCode第一个题目，题目如下：

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

算法一句话概括就是从数组里面取2个数若和为9则返回下标。我用C写出来后却报错了。我把代码放在VC6.0上运行却是成功的，代码如下：

/**
 * Note: The returned array must be malloced, assume caller calls free().
 */
int* twoSum(int* nums, int numsSize, int target) {
     int *indice = (int*)malloc(2*sizeof(int)); 
    for(int i=0;i<=numsSize-1;i++){
        for(int j=0;j<=numsSize-1;j++){
            if((nums[i]+nums[j]==target)&(i!=j)){
                indice[1]=i;
                indice[0]=j;
            }
        }
    }
    return indice;
}
void main(void){
    int nums[4]={2,7,11,15},target=9,numsSize=4;
    int* p=twoSum(nums,numsSize,target);
    printf("[%d,%d]\n",p[0],p[1]);
}

代码运行结果如下：

watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3FxXzM5NDYzMTc1_size_16_color_FFFFFF_t_70

我提交后却是：

后来发现与系统自带main冲突，思考了2下，突然灵光一现，去掉main函数提交不就行了：

/**
 * Note: The returned array must be malloced, assume caller calls free().
 */
int* twoSum(int* nums, int numsSize, int target) {
     int *indice = (int*)malloc(2*sizeof(int)); 
    for(int i=0;i<=numsSize-1;i++){
        for(int j=0;j<=numsSize-1;j++){
            if((nums[i]+nums[j]==target)&(i!=j)){
                indice[1]=i;
                indice[0]=j;
            }
        }
    }
    return indice;
}