Two Sum
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
解法:
class Solution {
public:
vector<int> twoSum(vector<int>& nums, int target) {
vector<int> vect;
for(int i = 0; i < nums.size(); ++i)
{
for (int j = i+1; j < nums.size(); ++j)
{
if (nums[i] + nums[j] == target)
{
vect.push_back(i);
vect.push_back(j);
}
}
}
return vect;
}
};
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