MySQL之Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in...
解决:
在$data = mysqli_query($dbc, $query);后加上这样一段代码:
$result = mysqli_query($this->conn, $this->sql);
if (!$result) {
printf("Error: %s\n", mysqli_error($this->conn));
//exit();
参考文章:
https://zhidao.baidu.com/question/550445087.html
还没有评论,来说两句吧...