Warning: json_encode() expects parameter 2 to be long, string given in

﹏ヽ暗。殇╰゛Y 2022-12-20 06:00 204阅读 0赞

# 问题描述： #

`Warning: json_encode() expects parameter 2 to be long, string given in app\controller\BaseController.php on line 80`

出错部分代码：

function jsonResult( $state = 0, $message = "", $data = array(), $total = 0, $pageSize = 0 )
        { 
            return json_encode(array('state' => $state, 'message' => $message, 'data' => $data, 'total' => $total, 'pageSize' => $pageSize), JSON_UNESCAPED_UNICODE);
        }

--------------------

# 原因分析： #

常量JSON\_UNESCAPED\_UNICODE仅适用于PHP版本> = 5.4。其值为256。（当前项目php 版本为5.3.29）

define ('JSON_UNESCAPED_UNICODE', 256);

--------------------

# 解决方案： #

将“JSON\_UNESCAPED\_UNICODE”替换成256。

function jsonResult( $state = 0, $message = "", $data = array(), $total = 0, $pageSize = 0 )
        { 
            /** * define ('JSON_UNESCAPED_UNICODE', 256); * 将“JSON_UNESCAPED_UNICODE”替换成256，避免出现如下警告（版本<5.4）： * json_encode() expects parameter 2 to be long, string given in */
            return json_encode(array('state' => $state, 'message' => $message, 'data' => $data, 'total' => $total, 'pageSize' => $pageSize), 256);
        }

--------------------

**参考文章：**  
[https://www.it1352.com/1509071.html][https_www.it1352.com_1509071.html]

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