杭电1012
u Calculate e
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 18822 Accepted Submission(s): 8211
Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
//杭电1012
#include <stdio.h>
int main (int argc, char **argv)
{
printf("n e\n");
printf("- -----------\n");
printf("0 1\n");
printf("1 2\n");
printf("2 2.5\n");
double result = 2.5 ;
double p = 0.5;
for (int i = 3; i <= 9; ++ i )
{
p /= i;
result += p;
printf("%d %.9f\n", i , result);
}
return 0;
}
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