Maximum Level Sum of a Binary Tree(C++ 最大层内元素和)
解题思路:
(1)使用map记录每层元素的和
(2)分层比较大小
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
void pre_order(TreeNode *root,int h,unordered_map<int,int> &mp) {
if(root==NULL) return;
mp[h]+=root->val;
pre_order(root->left,h+1,mp);
pre_order(root->right,h+1,mp);
}
int maxLevelSum(TreeNode* root) {
unordered_map<int,int> mp;
pre_order(root,1,mp);
int level=-1,max=-100001;
for(auto it=mp.begin();it!=mp.end();it++) {
if(it->second>=max) {
max=it->second;
level=it->first;
}
}
return level;
}
};
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