PE 118-119 (dfs+暴力)
PE 118
题解:next_permutation()+dfs就可以了
代码:
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int ans=0;
vector<int>v;
int isprime(ll n)
{
if(n==1)return 0;
for(ll i=2;i*i<=n;i++){
if(n%i==0)return 0;
}
return 1;
}
void dfs(int pos,ll now){
if(pos>=9){
if(ans<=10){
//for(int i=0;i<9;i++)
//cout<<v[i]<<" ";
//cout<<endl;
}
ans++;return;
}
ll n = 0;
while(pos < 9){
n *= 10;
n += v[pos];
if(isprime(n) && n >= now){
dfs(pos+1,n);
}
pos++;
}
}
int main()
{
for(int i=1;i<=9;i++){v.push_back(i);}
do{
dfs(0,0);
}while(next_permutation(v.begin(),v.end()));
cout<<"ans="<<ans<<endl;
return 0;
}
PE 119
题解:暴力….
代码:
#include<bits/stdc++.h>
using namespace std;
long long gao(int m,int n)
{
long long res=(long long)pow(m,n);
long long ans=0;
while(res)
{
ans+=res%10;
res/=10;
}
return ans;
}
set<long long>s;
int main()
{
for(int i=1;i<=100;i++)
{
for(int j=1;j<=100;j++)
{
if((long long)gao(j,i)==(long long)j)
{
s.insert(pow(j,i));
}
}
}
int num=1;
for(set<long long>::iterator it = s.begin();it !=s.end();it++)
{
if(*it>=10)
cout<<num++<<":"<<*it<<endl;
}
return 0;
}
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