1108 Finding Average (20 分) 字符串处理 sscanf和sprintf 格式化-蒲公英云

1108 Finding Average (20 分) 字符串处理 sscanf和sprintf 格式化

The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−1000,1000] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤100). Then N numbers are given in the next line, separated by one space.

Output Specification:

For each illegal input number, print in a line ERROR: X is not a legal number where X is the input. Then finally print in a line the result: The average of K numbers is Y where K is the number of legal inputs and Y is their average, accurate to 2 decimal places. In case the average cannot be calculated, output Undefined instead of Y. In case K is only 1, output The average of 1 number is Y instead.

Sample Input 1:

7
5 -3.2 aaa 9999 2.3.4 7.123 2.35

Sample Output 1:

ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38

Sample Input 2:

2
aaa -9999

Sample Output 2:

ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined

题意：把合法的数字加起来算平均值，合法:[-1000，1000]的最多两位小数的数。

发现了一个神奇的东西！sscanf和sprintf 格式化！省去了很多判断！

sscanf与scanf等价，所不同的是，前者的输入字符来源于字符串s，而scanf以stdin作为输入源。

sscanf(“123456 “, “%4s”, buf); 取指定长度的字符串

取到指定字符为止的字符串。如在下例中，取遇到空格为止字符串。
　　sscanf(“123456 abcdedf”, “%[^ ]“, buf);
　　printf(“%s\n”, buf);
　　结果为：123456

sprintf(s, “%d”, 123); //产生”123”

更多用法：https://www.cnblogs.com/wangtianxj/archive/2009/07/04/1516646.html

#include<stdio.h>
#include<string.h>
#include<math.h>
#include<iostream>
using namespace std;
int main()
{
    int n,i,j,l,sum=0;//sum 合法数 
    double s=0,temp;
    char a[105],b[105];
    scanf("%d",&n);
    for(i=0;i<n;i++)
    {
        int f=0;
        scanf("%s",a);
        sscanf(a,"%lf",&temp);
        sprintf(b,"%.2f",temp);
        //cout<<a<<" "<<b<<" "<<temp<<endl;
        for(int j=0;j<strlen(a);j++)
        {
             if(a[j]!=b[j]) f=1;
        }
        if(f||temp<-1000|| temp>1000)
        {
            printf("ERROR: %s is not a legal number\n",a);
            continue;
        }
        else
        {
            s+=temp;
            sum++;
        }
    }
    if(sum==0)
    printf("The average of 0 numbers is Undefined\n");
    else if(sum==1)
    printf("The average of 1 number is %.2lf\n",s/sum);
    else
    printf("The average of %d numbers is %.2lf\n",sum,s/sum);
}